![abstract algebra - Substitution principle example? (for ring homomorphisms $R[x]\to S$) - Mathematics Stack Exchange abstract algebra - Substitution principle example? (for ring homomorphisms $R[x]\to S$) - Mathematics Stack Exchange](https://i.stack.imgur.com/hlYNb.png)
abstract algebra - Substitution principle example? (for ring homomorphisms $R[x]\to S$) - Mathematics Stack Exchange
![SOLVED: Definition: Let o: R = be a ring homomorphism between rings Then the kernel of 0 is ker(o) = re R:o(r) = 0. Proposition 2.0 If 0: R 7 5 i SOLVED: Definition: Let o: R = be a ring homomorphism between rings Then the kernel of 0 is ker(o) = re R:o(r) = 0. Proposition 2.0 If 0: R 7 5 i](https://cdn.numerade.com/ask_images/feed107dd00e4ab8aab2f799d810b79c.jpg)
SOLVED: Definition: Let o: R = be a ring homomorphism between rings Then the kernel of 0 is ker(o) = re R:o(r) = 0. Proposition 2.0 If 0: R 7 5 i
![SOLVED: Question 2 [19 marks] (a) Define what is meant by a ring homomorphism between two rings R and S, and define what is meant by its kernel: (6) Suppose that 0 SOLVED: Question 2 [19 marks] (a) Define what is meant by a ring homomorphism between two rings R and S, and define what is meant by its kernel: (6) Suppose that 0](https://cdn.numerade.com/ask_images/44065acaa9c74122a98d33e110a8359a.jpg)
SOLVED: Question 2 [19 marks] (a) Define what is meant by a ring homomorphism between two rings R and S, and define what is meant by its kernel: (6) Suppose that 0
![abstract algebra - Does a ring homomorphism necessarily induce a map of their spectrums? - Mathematics Stack Exchange abstract algebra - Does a ring homomorphism necessarily induce a map of their spectrums? - Mathematics Stack Exchange](https://i.stack.imgur.com/Rfy7U.png)